Better: take the string as a whole — but first, does it contain % signs? No, it’s plain text. But %3D would be = . If it's double-encoded, %25 is % . So %3D becomes = in first decode.
In fact, %3D appears if I decode certain parts: %3D is = in URL encoding. Let me try interpreting it as first. Better: take the string as a whole —
Given the context ("feature" in your message), maybe this is a puzzle or test string. I notice feature might be the answer? No. If it's double-encoded, %25 is %
But cm1ha2Vy — that is rmaker only if it's cmFrZXI= (maker) — wait cmFrZXI= is maker in base64. Yes: cmFrZXI= base64 → maker . So cm1ha2Vy with 1 instead of F ? No, cmFrZXI= has Fr not 1h . Let me try interpreting it as first
jtdcjtiyaxnfc3rhcm1ha2vyx2f1dg8lmjilm0f0cnvljtjdjtiyzgvlcgxpbmslmjilm0elmjjzbsuzqsuyriuyrnbsyxlyzwnv That’s 104 chars. Base64 length should be multiple of 4. 104 is multiple of 4. Let's decode:
Decode in Python mental simulation: first 4 chars jtdc → base64 decode gives 3 bytes. But j is not standard base64 (A-Z a-z 0-9 + /). j is allowed (lowercase), so okay. But the result will likely be binary or another encoding.
Let me try the whole string: