H₀: μ = 500, H₁: μ < 500 (one‑tailed) Test statistic t = (490‑500)/(25/√30) = –10 / 4.564 = –2.19 Critical t₀.₀₅,₂₉ = –1.699 (left tail) Since –2.19 < –1.699 → Reject H₀ . Conclusion: There is sufficient evidence that the mean battery life is less than 500 hours. What to Expect in the Complete PDF The full Probability and Statistics Exercises with Solutions PDF (40 pages) includes:
n=50 → df=49 → t₀.₀₂₅ ≈ 2.01 (using t‑distribution) Margin of error = 2.01 × (100/√50) = 2.01 × 14.142 ≈ 28.43 CI = 1200 ± 28.43 → (1171.57, 1228.43) hours 6. Hypothesis Testing Problem: A manufacturer claims that their batteries last 500 hours on average. A sample of 30 batteries has a mean of 490 hours and standard deviation of 25 hours. Test at α=0.05 whether the mean is less than 500 hours. probability and statistics exercises with solutions pdf
| Topic | Number of Problems | |-------|--------------------| | Descriptive statistics | 8 | | Set theory & probability axioms | 10 | | Conditional probability & Bayes’ theorem | 6 | | Discrete distributions (Binomial, Poisson) | 8 | | Continuous distributions (Normal, Exponential) | 7 | | Sampling distributions & CLT | 5 | | Confidence intervals | 6 | | Hypothesis testing (z‑test, t‑test, χ² test) | 8 | | Linear regression & correlation | 4 | H₀: μ = 500, H₁: μ < 500