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A = [3 -1 2; -2 4 1; 5 2 -3]; b = [1; 2; 3]; [L, U, P] = luDecomp(A); % P is permutation matrix
I’ve put together an explanatory piece based on the context of (and its solution) from the Solution Manual for Jaan Kiusalaas’ Numerical Methods in Engineering with MATLAB , 2nd Edition. A = [3 -1 2; -2 4 1;
Since the specific problem statement from the manual isn’t visible to me, I’ll reconstruct the likely problem type (based on the book’s known structure: Chapter 2, Systems of Linear Equations) and show how the solution manual would solve it step-by-step using MATLAB. Topic: Solving a system of linear equations using LU decomposition with partial pivoting (or determining the inverse of a matrix via LU). Typical problem statement: Given the matrix ( A ) and vector ( b ): [ A = \beginbmatrix 3 & -1 & 2 \ -2 & 4 & 1 \ 5 & 2 & -3 \endbmatrix, \quad b = \beginbmatrix 1 \ 2 \ 3 \endbmatrix ] Solve ( A x = b ) using LU decomposition with partial pivoting. Then compute the inverse of ( A ) using the same LU factors. Solution from the Solution Manual (Step-by-Step) Step 1: Perform LU decomposition with partial pivoting In MATLAB, using Kiusalaas’ custom function luDecomp (from the book’s utility functions): Typical problem statement: Given the matrix ( A